home | O'Reilly's CD bookshelfs | FreeBSD | Linux | Cisco | Cisco Exam  

Book HomePerl CookbookSearch this book

16.7. Reading STDERR from a Program


You want to run a program as you would with system , backticks, or open , but you don't want its STDERR to be sent to your STDERR. You would like to be able to either ignore or read the STDERR.


Use the shell's numeric redirection and duplication syntax for file descriptors. (We don't check the return value from open here, to make the examples easier to read, but you should always check it in your programs!)

To capture a command's STDERR and STDOUT together:

$output = `cmd 2>&1`;                          # with backticks
# or
$pid = open(PH, "cmd 2>&1 |");                 # with an open pipe
while (<PH>) { }                               # plus a read

To capture a command's STDOUT and discard its STDERR:

$output = `cmd 2>/dev/null`;                   # with backticks
# or
$pid = open(PH, "cmd 2>/dev/null |");          # with an open pipe
while (<PH>) { }                               # plus a read

To capture a command's STDERR and discard its STDOUT:

$output = `cmd 2>&1 1>/dev/null`;              # with backticks
# or
$pid = open(PH, "cmd 2>&1 1>/dev/null |");     # with an open pipe
while (<PH>) { }                               # plus a read

To exchange a command's STDOUT and STDERR, i.e., capture the STDERR but have its STDOUT come out on our old STDERR:

$output = `cmd 3>&1 1>&2 2>&3 3>&-`;           # with backticks
# or
$pid = open(PH, "cmd 3>&1 1>&2 2>&3 3>&-|");   # with an open pipe
while (<PH>) { }                               # plus a read

To read both a command's STDOUT and its STDERR separately, it's easiest and safest to redirect them separately to files, and then read from those files when the program is done:

system("program args 1>/tmp/program.stdout 2>/tmp/program.stderr");


When you launch a command with backticks, a piped open , or system on a single string, Perl checks for characters special to the shell. These allow you to redirect the new program's file descriptors. STDIN is file descriptor number 0, STDOUT number 1, and STDERR number 2. You can then use 2> file to redirect STDERR to a file. The special notation &N where N is a file descriptor number is used to redirect to a file descriptor. Therefore, 2>&1 points STDERR at STDOUT.

Here is a table of interesting shell file descriptor redirections:




Make STDIN give immediate EOF


Discard STDOUT


Discard STDERR


Send STDERR to STDOUT instead


Close STDERR (not recommended)


Open fd 3 to /dev/tty in read-write mode

Using this, let's examine the most complicated of the redirection sequences from the solution section:

$output = `cmd 3>&1 1>&2 2>&3 3>&-`;        

There are four steps here:

Step A: 3>&1

Make a new file descriptor, number 3, be a copy of number 1. This saves where STDOUT had been destined in the new file descriptor we've just opened.

Step B: 1>&2

Make STDOUT go wherever STDERR had been going. We still have the saved destination squirreled away in descriptor 3.

Step C: 2>&3

Make file descriptor 2 a copy of number 3. That means that STDERR is now going out where STDOUT had been originally going.

Step D: 3>&-

Since we're done moving streams around, keep everything nice and tidy and close our temporary file descriptor. This avoids file descriptor leaks.

If that's confusing, it might help to think in terms of regular variables and a sequence of assignment statements, with $fd1 representing STDOUT and $fd2 representing STDERR. If you wanted to exchange the two variables, you'd use a temporary to hold one value. That's all we're doing here.

$fd3 = $fd1;
$fd1 = $fd2;
$fd2 = $fd3;
$fd3 = undef;

When all's said and done, the string returned from the backticks is the command's STDERR, and its STDOUT has been diverted to the original STDERR.

Ordering is important in all these examples. That's because the shell processes file descriptor redirections in strictly left to right order.

system("prog args 1>tmpfile 2>&1");
system("prog args 2>&1 1>tmpfile");

The first command sends both standard out and standard error to the temporary file. The second command sends only the old standard output there, and the old standard error shows up on the old standard out. If that's confusing, think in terms of assignments to variables representing file descriptors:

# system ("prog args 1>tmpfile 2>&1");
$fd1 = "tmpfile";        # change stdout destination first
$fd2 = $fd1;             # now point stderr there, too

is very different from:

# system("prog args 2>&1 1>tmpfile");
$fd2 = $fd1;             # stderr same destination as stdout
$fd1 = "tmpfile";        # but change stdout destination 

See Also

Your system's sh (1) manpage (if you have one) for details about file descriptor redirection; the system function in Chapter 3 of Programming Perl and in perlfunc (1)

Previous: 16.6. Preprocessing Input Perl Cookbook Next: 16.8. Controlling Input and Output of Another Program
16.6. Preprocessing Input Book Index 16.8. Controlling Input and Output of Another Program

Library Navigation Links

Copyright © 2002 O'Reilly & Associates. All rights reserved.