home | O'Reilly's CD bookshelfs | FreeBSD | Linux | Cisco | Cisco Exam ## 3.6. Day in a Week/Month/Year or Week Number

### Problem

You have a date, either in Epoch seconds or as distinct year, month, etc. values. You want to find out what week of the year, day of the week, day of the month, or day of the year that the date falls on.

### Solution

If you have Epoch seconds, the day of the year, day of the month, and day of the week are returned by ``` localtime``` . The week of the year is easily calculated from the day of the year (but see discussion below, as standards differ).

```(\$MONTHDAY, \$WEEKDAY, \$YEARDAY) = (localtime \$DATE)[3,6,7];
\$WEEKNUM = int(\$YEARDAY / 7) + 1;```

If you have distinct DMYHMS values, you can either convert them to Epoch seconds values as in Recipe 3.3 and then use the solution above, or else use the ``` Day_of_Week``` , ``` Week_Number``` , and ``` Day_of_Year``` functions from the CPAN module Date::Calc:

```use Date::Calc qw(Day_of_Week Week_Number Day_of_Year);
# you have \$year, \$month, and \$day
# \$day is day of month, by definition.
\$wday = Day_of_Week(\$year, \$month, \$day);
\$wnum = Week_Number(\$year, \$month, \$day);
\$dnum = Day_of_Year(\$year, \$month, \$day);```

### Discussion

The ``` Day_of_Week``` , ``` Week_Number``` , and ``` Day_of_Year``` functions all expect years that haven't had 1900 subtracted from them and months where January is 1, not 0. The return value from ``` Day_of_Week``` can be 1 through 7 (corresponding to Monday through Sunday) or 0 in case of an error (an invalid date, for example).

```use Date::Calc qw(Day_of_Week Week_Number Day_of_Week_to_Text)

\$year  = 1981;
\$month = 6;         # (June)
\$day   = 16;

\$wday = Day_of_Week(\$year, \$month, \$day);
print "\$month/\$day/\$year was a ", Day_of_Week_to_Text(\$wday), "\n";
## see comment above

\$wnum = Week_Number(\$year, \$month, \$day);
print "in the \$wnum week.\n";
```

6/16/1981 was a Tuesday

```

```

in week number 25.

```
```

The governing standards body of particular countries may have rules about when the first week of the year starts. For example, in Norway the first week must have at least 4 days in it (and weeks start on Mondays). If January 1 falls on a week with 3 or fewer days, it is counted as week 52 (or 53) of the previous year. In America, the first Monday of the year is usually the start of the first work-week. Given such rules, you may have to write your own algorithm, or at least look at the ``` %G``` , ``` %L``` , ``` %W``` , and ``` %U``` formats to the ``` UnixDate``` function in Date::Manip.

The ``` localtime``` function in perlfunc (1) and Chapter 3 of Programming Perl ; the documentation for the CPAN module Date::Calc   3.5. Difference of Two Dates 3.7. Parsing Dates and Times from Strings 