imagecreatefromjpeg

(PHP 4, PHP 5)

imagecreatefromjpeg — Create a new image from file or URL

Description

resource imagecreatefromjpeg ( string $filename )

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

On failure imagecreatefromjpeg() outputs an error message, which unfortunately displays as a broken link in a browser. To ease debugging the following example will produce an error JPEG:

Example#1 Example to handle an error during creation


<?php
function LoadJpeg($imgname)
{
    $im = @imagecreatefromjpeg($imgname); /* Attempt to open */
    if (!$im) { /* See if it failed */
        $im  = imagecreatetruecolor(150, 30); /* Create a black image */
        $bgc = imagecolorallocate($im, 255, 255, 255);
        $tc  = imagecolorallocate($im, 0, 0, 0);
        imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
        /* Output an errmsg */
        imagestring($im, 1, 5, 5, "Error loading $imgname", $tc);
    }
    return $im;
}
header("Content-Type: image/jpeg");
$img = LoadJpeg("bogus.image");
imagejpeg($img);
?>

The above example will output something similar to:

Tip

You can use a URL as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and List of Supported Protocols/Wrappers for a list of supported URL protocols.

Parameters

filename: Path to the JPEG image

Return Values

Returns an image resource identifier on success, FALSE on errors.

Notes

Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.

Warning

Windows versions of PHP prior to PHP 4.3.0 do not support accessing remote files via this function, even if allow_url_fopen is enabled.