4.1.1 References to Named Subroutines

We saw earlier that to take a reference to an existing variable, we prefix it with a backslash. It is much the same with subroutines. \&mysub is a reference to &mysub . For example:

sub greet {
    print "hello \n";
}
$rs = \&greet; # Create a reference to subroutine greet

It is important to note that we are not calling the greet subroutine here, in the same way that we don't evaluate the value of a scalar when we take a reference to it.

Contrast this to the following code, which uses parentheses:

$rs = \&greet();

This expression likely doesn't do what you expect. It calls greet and produces a reference to its return value , which is the value of the last expression evaluated inside that subroutine. Since print executed last and returned a 1 or a 0 (indicating whether or not it was successful in printing the value), the result of this expression is a reference to a scalar containing 1 or 0! These are the kind of mistakes that make you wish for type-safety once in a while!

To summarize, do not use parentheses when taking a subroutine reference.

4.1.2 References to Anonymous Subroutines

You can create an anonymous subroutine simply by omitting the name in a subroutine declaration. In every other respect, the declaration is identical to a named one.

$rs = sub {
           print "hello \n";
      };

This expression returns a reference to the newly declared subroutine. Notice that because it is an expression, it requires the semicolon at the end, unlike the declaration of a named subroutine.

4.1.3 Dereferencing Subroutine References

Dereferencing a subroutine reference calls the subroutine indirectly. As with data references, Perl does not care whether $rs is pointing to a named or an anonymous subroutine; dereferencing works the same way in either case.

It should come as no surprise that prepending $rs with the appropriate prefix - " & ", in this case - dereferences it:

&$rs
(10, 20);  # Call the subroutine indirectly

That's all there is to it.

Just as you can use the -> syntax with arrays or hashes ( $ra->[10] or $rh->{'k2'} ), you can call subroutines indirectly through references, like this:

$rsub->(10);

In fact, subroutine calls can be chained if the intermediate calls return subroutine references. For example:

$rs = \&test1;
$rs->("Batman")->("Robin"); # Prints "Batman and Robin"

sub test1 {
    my $arg = shift;
    print "$arg";
    return \&test2;
}
sub test2 {
    my $arg = shift;
    print " and $arg\n";
}

4.1.4 Symbolic References

Recall that symbolic references contain names (strings), not real references. There is no difference in syntax between real and symbolic references. Consider

sub foo { print "foo called\n" }
$rs = "foo"; 
&$rs();  # prints "foo called"

Using symbolic references is a mite slower than using real references.